Different types of matrices can be recognized:
Matrices can be manipulated if the rules noted below are satisfied.
Element a (first row and first column) of the product matrix is equal to the product of the first row of the pre times the first column of the post. Element d (second row and second column) of the product matrix is equal to the product of the second row of the pre times the second column of the post.
Consider the pair of simultaneous equations:
Consider the following matrix:
The determinant (usually written as |a| for matrix A) is given by subtracting the product of the two off the main diagonal elements (10 times 10) from the product of the elements on the main diagonal (4 times 30) or |a| = 120 - 100 or 20.
Determinants can be computed for larger square matricies (Cramer's Rule).
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If X 7 6 X' 7 5
5 4 6 4
7 6 1 5 6 1
Thus, A(2,1) = B(2,1)+C(2,1) or 0 = -1 + 1
= +
0 4 -1 2 1 2
8 3 9 5 1 1
Thus, A(2,1) = B(2,1)-C(2,1) or 5 = 9 - 4
= -
5 7 9 9 4 2
a b 9 5 1 1
= *
c d 9 9 4 2
a = 9*1 + 5*4 = 20
b = 9*1 + 5*2 = 19
c = 9*1 + 9*4 = 45
d = 9*1 + 9*2 = 27
4X1 + 10X2 = 38
10X1 + 30X2 = 110
Let matrix A be the matrix of coefficients of the equations:
4 10
10 30
Let B be the solution vector:
38
110
Let X be the vector of unknowns:
X1
X2
The equations can be written:
AX = B
If ordinary division held, then X = B/A which is undefined for matricies.
The inverse of a matrix A (written as A-1)is a matrix which satisfies the relationship:
A-1A = I
or the product of the inverse of a matrix times the matrix equals the identify matrix I.
For the matrix A defined above show that AI (or IA) = A.
Thus, the identify matrix operates like multiplying a number by 1.0.
(in the above, if A is a 3 by 3 matrix then the identity matrix is a 3 by 3
matrix with 1s on the main diagonal and 0s in all of the other positions.
If both sides of the equation are multiplied by A-1 then:
AA-1X = BA-1
since AA-1 = I then
IX=BA-1 or
X = BA-1.
The vector of unknowns equals the product matrix formed by pre multiplying
the inverse of the coefficients matrix by the constant vector.
Show for yourself that the dimensions of the matrices and vectors satisfy
the rules for multiplication.
Many books and articles have been written on the general subject of finding
the inverse of a matrix. In our work we will be dealing with finding
the inverse of a square and symmetric matrix.
Singular matrices have no inverse.
4 10
10 30