Several authors (including our own Dr. WW) have speculated that the depth to an active subduction zone influences the chemical composition of liquids produced by partial melting above the subducting slab. Data given below were gathered as follows. Suites of igneous rocks from known subduction zone complexes were analyzed for major elements. For each suite a binary plot was made of K2O versus SiO2 and a best fit straight line drawn by eye through the points. The amount of K2O at 57.5% SiO2was determined for each suite. These values and the depths to the subduction zone appear below for 17 suites. Depth is given in Km and K2O in weight percent. Ulitmately, the goal of these authors was to be able to measure the K2 in a volcanic rock produced by partial melting near a subduction zone and then estimate the depth to the subduction zone. This would allow the reconstruction of the geometry of subducting slabs that no longer exist.
Simple linear regression models are available on Data Desk.
Suite Depth K2O
The column t-ratio holds the test-statistics for assessing whether the slope coefficient or the constant term are 0.0. Compare the values of t-ratio with the appropriate t-statistic (page 95). If the null is rejected, the value differes significantly from 0.0. If, for example, you accept the null hypotheses you are claiming that knowledge of X tells you nothing about the value of Y. In this case the best estimate of Y is the mean of all of the Y values. As the correlation coefficient decreases, the likelyhood of accepting the null hypothesis increases. Evaluate the two t-ratios for this example. These are two-tailed tests - the null is that the coefficient equals 0.0 and the alternative is that it does not equal 0.0. Select a significant level 0f 5%.
The middle part of the table is these results of an Analysis of Variance. See page 22-7 for an explanation of the ANOVA part of the regression summary.
The form of the equation is Yi = Gx + BxXi where Gx is the intercept and Bx the slope. The user picks one variable to be designated as X and the other as Y. There is NO implication as to dependence versus independence as there is with regression analysis.
The absolute value of Bx is given by the ratio sy/sx (where s is the standard deviation). The sign of the slope is given by the sign of the correlation coefficient.
Gx = Yy - BxXx where Bx is defined as above and Y and X are the means of the variables designated as Y and X respectively.
Example:
Y: sy = 0.79 and mean = 21.4
X: sx = 1.38 and mean = 43.4
rx,y is negative
|Bx| = (.79/1.38) = .572; as r is -, Bx = -.572.
Gx = 21.4-(-.572*43.4) = 46.2
Therefore, Yi = 46.2 - 0.572Xi
If you reverse your assignment of X and Y, you should obtain the same equation - try it and see.
Plot this line on your hard copy and label it as the line or organic correlation. This line should pass through the point of intersection of XonY and YonX.
tx = r((N-2)/(1-r2)).5
if tx is > student's t with (N-1) d.f. the null is rejected
Evaluate the correlation between this pair of variables.