Problem: Isotonic saline is 0.15 M NaCl(aq). How would you prepare 0.800 L isotonic saline from a 6.0 M stock solution?
56
Plan:
Solution: Finding moles of solute in dilute solution:
Since we add only solvent to dilute the solution,
Mol of NaCl in diluted soln = mol of NaCl in concentrated solín.
= 0.12 mol NaCl
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