8
Step 5. The C on the right has an octet, but the C on the left has only 6e – , so convert the lone pair to another bonding pair between the two C atoms:
(b) For N 2 . After Steps 1 to 4 we have:
Step 5. Neither N has an octet, so change a lone pair to bonding pair:
Moving one lone pair to make a double bond still doesn’t give each N an octet, so we move another lone pair to make a triple bond:
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